Tuesday 17 July 2012

UVa 12043 - Divisors Solution

#include<iostream>
#include<list>
#include<string>
#include<cstring>
#include<sstream>
#include<cctype>
#include<string.h>
#include<algorithm>
#include<cmath>
#include<stack>
#include<fstream>
#include<cstdlib>
#include<vector>
#include<map>
#include<set>
#include<utility>
#include<iomanip>
#include<queue>

using namespace std;

#define INF (1<<29)
#define SET(a) memset(a,-1,sizeof(a))
#define ALL(a) a.begin(),a.end()
#define CLR(a) memset(a,0,sizeof(a))
#define FILL(a,v) memset(a,v,sizeof(a))
#define PB push_back
#define FOR(i,n) for(int i = 0;i<n;i++)
#define PI acos(-1.0)
#define EPS 1e-9
#define MP(a,b) make_pair(a,b)
#define min3(a,b,c) min(a,min(b,c))
#define max3(a,b,c) max(a,max(b,c))
#define READ(f) freopen(f, "r", stdin)
#define WRITE(f) freopen(f, "w", stdout)
#define LL long long
#define MX 100010
#define MOD 1000000007

int main()
{
    LL s[MX],d[MX],a,b,k,g,h,t,sqt;

    d[1]=1;
    s[1]=1;
    for(LL i=2;i<MX;i++)
    {
        d[i]=2;
        s[i]=1+i;
        sqt=sqrt(i);
        for(LL j=2;j<=sqt;j++)
            if(i%j==0)
            {
                d[i]+=2;
                s[i]+=j+i/j;
            }
        if(sqt*sqt==i)
            {
                d[i]--;
                s[i]-=sqt;
            }
    }

    cin>>t;
    while(t--)
    {
       cin>>a>>b>>k;
       LL div=a/k;
       if(div*k!=a)
       a=(div+1)*k;

       g=0;
       h=0;

       while(a<=b)
       {
           g+=d[a];
           h+=s[a];
           a+=k;
       }
       cout<<g<<" "<<h<<endl;
    }

return 0;
}

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