Saturday 2 June 2012

UVa 11340 Newspaper Solution

#include<stdio.h>
#include<string.h>
int main()
{
long int kase,c,val,line,i,j,k,len,n[200];
double price;
char text[10000],x[200];
while(scanf("%ld\n",&kase)==1)
{
for(k=1;k<=kase;k++)
{
price=0;
scanf("%ld\n",&val);
for(j=1;j<=val;j++)
{
scanf("%c%ld\n",&x[j],&n[j]);
}
scanf("%ld\n",&line);
for(j=1;j<=line;j++)
{
gets(text);
len=strlen(text);
for(i=1;i<=val;i++)
{
for(c=0;c<len;c++)
{
if(x[i]==text[c])price+=n[i];
}
}
}
printf("%.2lf$\n",price/100);
}
}
return 0;
}

1 comment: