/// Raihan Ruhin /// CSE, Jahangirnagar University. /// Dhaka-Bangladesh. /// id: raihanruhin (topcoder / codeforces / codechef / hackerrank / uva / uvalive / spoj), 3235 (lightoj) /// mail: raihanruhin@ (yahoo / gmail / facebook) /// blog: ruhinraihan.blogspot.com #include<bits/stdc++.h> using namespace std; #define SET(a) memset(a,-1,sizeof(a)) #define CLR(a) memset(a,0,sizeof(a)) #define PI acos(-1.0) #define MOD 1000000007 #define MX 100010 int main() { ios_base::sync_with_stdio(0);cin.tie(0); int n, a, b, c, d; string s; while(cin>>a>>b>>c>>d) { if(!a && !b && !c && !d) break; int ans=1080; if(a<b) ans+=(40+a-b)*9; else ans+=(a-b)*9; if(b>c) ans+=(40+c-b)*9; else ans+=(c-b)*9; if(c<d) ans+=(40+c-d)*9; else ans+=(c-d)*9; cout<<ans<<"\n"; } return 0; }
Thursday, 27 November 2014
UVA 10550 Combination Lock Solution (POJ 2304, ZOJ 1928)
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i couldn't understand the logic...explain please..
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