Monday, 6 August 2012

UVa 11679 - Sub-prime Solution

#include<iostream>
#include<list>
#include<string>
#include<cstring>
#include<sstream>
#include<cctype>
#include<string.h>
#include<algorithm>
#include<cmath>
#include<stack>
#include<fstream>
#include<cstdlib>
#include<vector>
#include<map>
#include<set>
#include<utility>
#include<iomanip>
#include<queue>

using namespace std;

#define INF (1<<29)
#define SET(a) memset(a,-1,sizeof(a))
#define ALL(a) a.begin(),a.end()
#define CLR(a) memset(a,0,sizeof(a))
#define FILL(a,v) memset(a,v,sizeof(a))
#define PB push_back
#define FOR(i,n) for(int i = 0;i<n;i++)
#define PI acos(-1.0)
#define EPS 1e-9
#define MP(a,b) make_pair(a,b)
#define min3(a,b,c) min(a,min(b,c))
#define max3(a,b,c) max(a,max(b,c))
#define READ freopen("input.txt", "r", stdin)
#define WRITE freopen("output.txt", "w", stdout)
#define LL long long
#define MX 1000010
#define MOD 1000000007


main()
{
    int account[20],b,n,c,d,v;
    while(cin>>b>>n)
    {
        if(!b && !n)
            break;

        for(int i=1;i<=b;i++)
            cin>>account[i];

        for(int i=1;i<=n;i++)
        {
            cin>>d>>c>>v;
            account[d]-=v;
            account[c]+=v;
        }
        bool chk=true;

        for(int i=1;i<=b;i++)
            if(account[i]<0)
                {
                    chk=false;
                    break;
                }
        if(chk)
            cout<<"S"<<endl;
        else
            cout<<"N"<<endl;
    }
}

1 comment:

  1. Please
    Can you explain why?

    for(int i=1;i<=b;i++)
    cin>>account[i];
    for(int i=1;i<=n;i++)
    {
    cin>>d>>c>>v;
    account[d]-=v;
    account[c]+=v;
    }

    ReplyDelete